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480x^2-18.17x-6.87=0
a = 480; b = -18.17; c = -6.87;
Δ = b2-4ac
Δ = -18.172-4·480·(-6.87)
Δ = 13520.5489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18.17)-\sqrt{13520.5489}}{2*480}=\frac{18.17-\sqrt{13520.5489}}{960} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18.17)+\sqrt{13520.5489}}{2*480}=\frac{18.17+\sqrt{13520.5489}}{960} $
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