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-x(x-6)=1
We move all terms to the left:
-x(x-6)-(1)=0
We multiply parentheses
-x^2+6x-1=0
We add all the numbers together, and all the variables
-1x^2+6x-1=0
a = -1; b = 6; c = -1;
Δ = b2-4ac
Δ = 62-4·(-1)·(-1)
Δ = 32
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32}=\sqrt{16*2}=\sqrt{16}*\sqrt{2}=4\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-4\sqrt{2}}{2*-1}=\frac{-6-4\sqrt{2}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+4\sqrt{2}}{2*-1}=\frac{-6+4\sqrt{2}}{-2} $
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