48/z+32=40

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Solution for 48/z+32=40 equation: 



48/z+32=40

We move all terms to the left:

48/z+32-(40)=0



Domain of the equation: z!=0

z∈R



We add all the numbers together, and all the variables

48/z-8=0

We multiply all the terms by the denominator


-8*z+48=0

We add all the numbers together, and all the variables

-8z+48=0

We move all terms containing z to the left, all other terms to the right

-8z=-48

z=-48/-8

z=+6

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