(1/2)+4=(2/3)x+1

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Solution for (1/2)+4=(2/3)x+1 equation: 



(1/2)+4=(2/3)x+1

We move all terms to the left:

(1/2)+4-((2/3)x+1)=0



Domain of the equation: 3)x+1)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((+2/3)x+1)+4+(+1/2)=0

We get rid of parentheses

-((+2/3)x+1)+4+1/2=0

We calculate fractions


()/3x+1)*2)+3x/3x+1)*2)+4=0

We calculate fractions


(()*3x)/9x^2+1*2)+3x*3x)/9x^2=0

We multiply all the terms by the denominator


(()*3x)+1*2)+3x*3x)=0



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Wy multiply elements

6x^2+(()*3x)=0



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