48-16(3u-4)+4u=4(16-u)

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Solution for 48-16(3u-4)+4u=4(16-u) equation: 



48-16(3u-4)+4u=4(16-u)

We move all terms to the left:

48-16(3u-4)+4u-(4(16-u))=0

We add all the numbers together, and all the variables

-16(3u-4)+4u-(4(-1u+16))+48=0

We add all the numbers together, and all the variables

4u-16(3u-4)-(4(-1u+16))+48=0

We multiply parentheses

4u-48u-(4(-1u+16))+64+48=0



We calculate terms in parentheses: -(4(-1u+16)), so:

4(-1u+16)

We multiply parentheses

-4u+64

Back to the equation:

-(-4u+64)



We add all the numbers together, and all the variables

-44u-(-4u+64)+112=0

We get rid of parentheses

-44u+4u-64+112=0

We add all the numbers together, and all the variables

-40u+48=0

We move all terms containing u to the left, all other terms to the right

-40u=-48

u=-48/-40

u=1+1/5

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