235=x2+2x-8

Solution for 235=x2+2x-8 equation:

235=x2+2x-8

We move all terms to the left:

235-(x2+2x-8)=0

We add all the numbers together, and all the variables

-(+x^2+2x-8)+235=0

We get rid of parentheses

-x^2-2x+8+235=0

We add all the numbers together, and all the variables

-1x^2-2x+243=0

a = -1; b = -2; c = +243;
Δ = b2-4ac
Δ = -22-4·(-1)·243
Δ = 976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{976}=\sqrt{16*61}=\sqrt{16}*\sqrt{61}=4\sqrt{61}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-4\sqrt{61}}{2*-1}=\frac{2-4\sqrt{61}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+4\sqrt{61}}{2*-1}=\frac{2+4\sqrt{61}}{-2}
$