48-(4c+4)=4(c+7)+7

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Solution for 48-(4c+4)=4(c+7)+7 equation: 



48-(4c+4)=4(c+7)+7

We move all terms to the left:

48-(4c+4)-(4(c+7)+7)=0

We get rid of parentheses

-4c-(4(c+7)+7)-4+48=0



We calculate terms in parentheses: -(4(c+7)+7), so:

4(c+7)+7

We multiply parentheses

4c+28+7

We add all the numbers together, and all the variables

4c+35

Back to the equation:

-(4c+35)



We add all the numbers together, and all the variables

-4c-(4c+35)+44=0

We get rid of parentheses

-4c-4c-35+44=0

We add all the numbers together, and all the variables

-8c+9=0

We move all terms containing c to the left, all other terms to the right

-8c=-9

c=-9/-8

c=1+1/8

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