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28x-2x^2=26
We move all terms to the left:
28x-2x^2-(26)=0
a = -2; b = 28; c = -26;
Δ = b2-4ac
Δ = 282-4·(-2)·(-26)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-24}{2*-2}=\frac{-52}{-4} =+13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+24}{2*-2}=\frac{-4}{-4} =1 $
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