47(n-12)-29(n-93)=n-88-6

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Solution for 47(n-12)-29(n-93)=n-88-6 equation: 



47(n-12)-29(n-93)=n-88-6

We move all terms to the left:

47(n-12)-29(n-93)-(n-88-6)=0

We add all the numbers together, and all the variables

47(n-12)-29(n-93)-(n-94)=0

We multiply parentheses

47n-29n-(n-94)-564+2697=0

We get rid of parentheses

47n-29n-n+94-564+2697=0

We add all the numbers together, and all the variables

17n+2227=0

We move all terms containing n to the left, all other terms to the right

17n=-2227

n=-2227/17

n=-131

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