41(99-5x)=-97(x+45)

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Solution for 41(99-5x)=-97(x+45) equation: 



41(99-5x)=-97(x+45)

We move all terms to the left:

41(99-5x)-(-97(x+45))=0

We add all the numbers together, and all the variables

41(-5x+99)-(-97(x+45))=0

We multiply parentheses

-205x-(-97(x+45))+4059=0



We calculate terms in parentheses: -(-97(x+45)), so:

-97(x+45)

We multiply parentheses

-97x-4365

Back to the equation:

-(-97x-4365)



We get rid of parentheses

-205x+97x+4365+4059=0

We add all the numbers together, and all the variables

-108x+8424=0

We move all terms containing x to the left, all other terms to the right

-108x=-8424

x=-8424/-108

x=+78

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