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46=(3x-2)+(2x)+(3x-2)+(2x)
We move all terms to the left:
46-((3x-2)+(2x)+(3x-2)+(2x))=0
We calculate terms in parentheses: -((3x-2)+2x+(3x-2)+2x), so:We get rid of parentheses
(3x-2)+2x+(3x-2)+2x
We add all the numbers together, and all the variables
4x+(3x-2)+(3x-2)
We get rid of parentheses
4x+3x+3x-2-2
We add all the numbers together, and all the variables
10x-4
Back to the equation:
-(10x-4)
-10x+4+46=0
We add all the numbers together, and all the variables
-10x+50=0
We move all terms containing x to the left, all other terms to the right
-10x=-50
x=-50/-10
x=+5
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