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1/2x-2=4x-3
We move all terms to the left:
1/2x-2-(4x-3)=0
Domain of the equation: 2x!=0We get rid of parentheses
x!=0/2
x!=0
x∈R
1/2x-4x+3-2=0
We multiply all the terms by the denominator
-4x*2x+3*2x-2*2x+1=0
Wy multiply elements
-8x^2+6x-4x+1=0
We add all the numbers together, and all the variables
-8x^2+2x+1=0
a = -8; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·(-8)·1
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-6}{2*-8}=\frac{-8}{-16} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+6}{2*-8}=\frac{4}{-16} =-1/4 $
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