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45x+9x=x2+5x=7x
We move all terms to the left:
45x+9x-(x2+5x)=0
We add all the numbers together, and all the variables
-(+x^2+5x)+45x+9x=0
We add all the numbers together, and all the variables
-(+x^2+5x)+54x=0
We get rid of parentheses
-x^2-5x+54x=0
We add all the numbers together, and all the variables
-1x^2+49x=0
a = -1; b = 49; c = 0;
Δ = b2-4ac
Δ = 492-4·(-1)·0
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-49}{2*-1}=\frac{-98}{-2} =+49 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+49}{2*-1}=\frac{0}{-2} =0 $
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