-(3x-(7x+4))=4+(3x+8)

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Solution for -(3x-(7x+4))=4+(3x+8) equation: 



-(3x-(7x+4))=4+(3x+8)

We move all terms to the left:

-(3x-(7x+4))-(4+(3x+8))=0



We calculate terms in parentheses: -(3x-(7x+4)), so:

3x-(7x+4)

We get rid of parentheses

3x-7x-4

We add all the numbers together, and all the variables

-4x-4

Back to the equation:

-(-4x-4)





We calculate terms in parentheses: -(4+(3x+8)), so:

4+(3x+8)

determiningTheFunctionDomain
(3x+8)+4

We get rid of parentheses

3x+8+4

We add all the numbers together, and all the variables

3x+12

Back to the equation:

-(3x+12)



We get rid of parentheses

4x-3x+4-12=0

We add all the numbers together, and all the variables

x-8=0

We move all terms containing x to the left, all other terms to the right

x=8

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