45=-2(b-5)+9b

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Solution for 45=-2(b-5)+9b equation: 



45=-2(b-5)+9b

We move all terms to the left:

45-(-2(b-5)+9b)=0



We calculate terms in parentheses: -(-2(b-5)+9b), so:

-2(b-5)+9b

We add all the numbers together, and all the variables

9b-2(b-5)

We multiply parentheses

9b-2b+10

We add all the numbers together, and all the variables

7b+10

Back to the equation:

-(7b+10)



We get rid of parentheses

-7b-10+45=0

We add all the numbers together, and all the variables

-7b+35=0

We move all terms containing b to the left, all other terms to the right

-7b=-35

b=-35/-7

b=+5

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