8x-3x=1/2(10x)

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Solution for 8x-3x=1/2(10x) equation:



8x-3x=1/2(10x)
We move all terms to the left:
8x-3x-(1/2(10x))=0
Domain of the equation: 210x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
8x-3x-(+1/210x)=0
We add all the numbers together, and all the variables
5x-(+1/210x)=0
We get rid of parentheses
5x-1/210x=0
We multiply all the terms by the denominator
5x*210x-1=0
Wy multiply elements
1050x^2-1=0
a = 1050; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·1050·(-1)
Δ = 4200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{4200}=\sqrt{100*42}=\sqrt{100}*\sqrt{42}=10\sqrt{42}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{42}}{2*1050}=\frac{0-10\sqrt{42}}{2100} =-\frac{10\sqrt{42}}{2100} =-\frac{\sqrt{42}}{210} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{42}}{2*1050}=\frac{0+10\sqrt{42}}{2100} =\frac{10\sqrt{42}}{2100} =\frac{\sqrt{42}}{210} $

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