45/5b=100

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Solution for 45/5b=100 equation: 



45/5b=100

We move all terms to the left:

45/5b-(100)=0



Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R



We multiply all the terms by the denominator


-100*5b+45=0

Wy multiply elements

-500b+45=0

We move all terms containing b to the left, all other terms to the right

-500b=-45

b=-45/-500

b=9/100

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