5(3y+2)=-28

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Solution for 5(3y+2)=-28 equation: 



5(3y+2)=-28

We move all terms to the left:

5(3y+2)-(-28)=0

We add all the numbers together, and all the variables

5(3y+2)+28=0

We multiply parentheses

15y+10+28=0

We add all the numbers together, and all the variables

15y+38=0

We move all terms containing y to the left, all other terms to the right

15y=-38

y=-38/15

y=-2+8/15

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