45-(2c+3)=4(c+7)+6

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Solution for 45-(2c+3)=4(c+7)+6 equation: 



45-(2c+3)=4(c+7)+6

We move all terms to the left:

45-(2c+3)-(4(c+7)+6)=0

We get rid of parentheses

-2c-(4(c+7)+6)-3+45=0



We calculate terms in parentheses: -(4(c+7)+6), so:

4(c+7)+6

We multiply parentheses

4c+28+6

We add all the numbers together, and all the variables

4c+34

Back to the equation:

-(4c+34)



We add all the numbers together, and all the variables

-2c-(4c+34)+42=0

We get rid of parentheses

-2c-4c-34+42=0

We add all the numbers together, and all the variables

-6c+8=0

We move all terms containing c to the left, all other terms to the right

-6c=-8

c=-8/-6

c=1+1/3

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