(1/4)x+(1/5)=(9/8)(-7x+7)

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Solution for (1/4)x+(1/5)=(9/8)(-7x+7) equation: 



(1/4)x+(1/5)=(9/8)(-7x+7)

We move all terms to the left:

(1/4)x+(1/5)-((9/8)(-7x+7))=0



Domain of the equation: 4)x!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 8)(-7x+7))!=0

x∈R



We add all the numbers together, and all the variables

(+1/4)x-((+9/8)(-7x+7))+(+1/5)=0

We multiply parentheses

x^2-((+9/8)(-7x+7))+(+1/5)=0

We get rid of parentheses

x^2-((+9/8)(-7x+7))+1/5=0

We multiply parentheses ..

x^2-((-63x^2+9/8*7))+1/5=0

We calculate fractions


x^2+(-((-63x^2+9*5)/()+()/()=0



We calculate terms in parentheses: +(-((-63x^2+9*5)/()+()/(), so:

-((-63x^2+9*5)/()+()/(

We can not solve this equation

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