4400=(1300-100p)p

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Solution for 4400=(1300-100p)p equation: 



4400=(1300-100p)p

We move all terms to the left:

4400-((1300-100p)p)=0

We add all the numbers together, and all the variables

-((-100p+1300)p)+4400=0



We calculate terms in parentheses: -((-100p+1300)p), so:

(-100p+1300)p

We multiply parentheses

-100p^2+1300p

Back to the equation:

-(-100p^2+1300p)



We get rid of parentheses

100p^2-1300p+4400=0

a = 100; b = -1300; c = +4400;
Δ = b2-4ac
Δ = -13002-4·100·4400
Δ = -70000
Delta is less than zero, so there is no solution for the equation

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