43=(3x+1)+(4x-14)

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Solution for 43=(3x+1)+(4x-14) equation: 



43=(3x+1)+(4x-14)

We move all terms to the left:

43-((3x+1)+(4x-14))=0



We calculate terms in parentheses: -((3x+1)+(4x-14)), so:

(3x+1)+(4x-14)

We get rid of parentheses

3x+4x+1-14

We add all the numbers together, and all the variables

7x-13

Back to the equation:

-(7x-13)



We get rid of parentheses

-7x+13+43=0

We add all the numbers together, and all the variables

-7x+56=0

We move all terms containing x to the left, all other terms to the right

-7x=-56

x=-56/-7

x=+8

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