35=5(1+z)

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Solution for 35=5(1+z) equation: 



35=5(1+z)

We move all terms to the left:

35-(5(1+z))=0

We add all the numbers together, and all the variables

-(5(z+1))+35=0



We calculate terms in parentheses: -(5(z+1)), so:

5(z+1)

We multiply parentheses

5z+5

Back to the equation:

-(5z+5)



We get rid of parentheses

-5z-5+35=0

We add all the numbers together, and all the variables

-5z+30=0

We move all terms containing z to the left, all other terms to the right

-5z=-30

z=-30/-5

z=+6

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