42=3x+3(4-4x)

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Solution for 42=3x+3(4-4x) equation: 



42=3x+3(4-4x)

We move all terms to the left:

42-(3x+3(4-4x))=0

We add all the numbers together, and all the variables

-(3x+3(-4x+4))+42=0



We calculate terms in parentheses: -(3x+3(-4x+4)), so:

3x+3(-4x+4)

We multiply parentheses

3x-12x+12

We add all the numbers together, and all the variables

-9x+12

Back to the equation:

-(-9x+12)



We get rid of parentheses

9x-12+42=0

We add all the numbers together, and all the variables

9x+30=0

We move all terms containing x to the left, all other terms to the right

9x=-30

x=-30/9

x=-3+1/3

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