42=1/2(2x+8)(x+3)

Solution for 42=1/2(2x+8)(x+3) equation:

42=1/2(2x+8)(x+3)

We move all terms to the left:

42-(1/2(2x+8)(x+3))=0


Domain of the equation: 2(2x+8)(x+3))!=0

x∈R


We multiply parentheses ..

-(1/2(+2x^2+6x+8x+24))+42=0

We multiply all the terms by the denominator


-(1+42*2(+2x^2+6x+8x+24))=0


We calculate terms in parentheses: -(1+42*2(+2x^2+6x+8x+24)), so:

1+42*2(+2x^2+6x+8x+24)

determiningTheFunctionDomain
42*2(+2x^2+6x+8x+24)+1

Wy multiply elements

84x(++1

We use the square of the difference formula

84x(+1

Back to the equation:

-(84x(+1)


We add all the numbers together, and all the variables

-(84x1=0