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1/2x-3=7x
We move all terms to the left:
1/2x-3-(7x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
-7x+1/2x-3=0
We multiply all the terms by the denominator
-7x*2x-3*2x+1=0
Wy multiply elements
-14x^2-6x+1=0
a = -14; b = -6; c = +1;
Δ = b2-4ac
Δ = -62-4·(-14)·1
Δ = 92
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{92}=\sqrt{4*23}=\sqrt{4}*\sqrt{23}=2\sqrt{23}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{23}}{2*-14}=\frac{6-2\sqrt{23}}{-28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{23}}{2*-14}=\frac{6+2\sqrt{23}}{-28} $
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