6=2(n-2)

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Solution for 6=2(n-2) equation: 



6=2(n-2)

We move all terms to the left:

6-(2(n-2))=0



We calculate terms in parentheses: -(2(n-2)), so:

2(n-2)

We multiply parentheses

2n-4

Back to the equation:

-(2n-4)



We get rid of parentheses

-2n+4+6=0

We add all the numbers together, and all the variables

-2n+10=0

We move all terms containing n to the left, all other terms to the right

-2n=-10

n=-10/-2

n=+5

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