42(3y-4)=88(y-1)

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Solution for 42(3y-4)=88(y-1) equation: 



42(3y-4)=88(y-1)

We move all terms to the left:

42(3y-4)-(88(y-1))=0

We multiply parentheses

126y-(88(y-1))-168=0



We calculate terms in parentheses: -(88(y-1)), so:

88(y-1)

We multiply parentheses

88y-88

Back to the equation:

-(88y-88)



We get rid of parentheses

126y-88y+88-168=0

We add all the numbers together, and all the variables

38y-80=0

We move all terms containing y to the left, all other terms to the right

38y=80

y=80/38

y=2+2/19

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