10+(1/5)y=2

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Solution for 10+(1/5)y=2 equation: 



10+(1/5)y=2

We move all terms to the left:

10+(1/5)y-(2)=0



Domain of the equation: 5)y!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(+1/5)y+10-2=0

We add all the numbers together, and all the variables

(+1/5)y+8=0

We multiply parentheses

y^2+8=0

a = 1; b = 0; c = +8;
Δ = b2-4ac
Δ = 02-4·1·8
Δ = -32
Delta is less than zero, so there is no solution for the equation

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