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41=(2x+2)+(3x+9)
We move all terms to the left:
41-((2x+2)+(3x+9))=0
We calculate terms in parentheses: -((2x+2)+(3x+9)), so:We get rid of parentheses
(2x+2)+(3x+9)
We get rid of parentheses
2x+3x+2+9
We add all the numbers together, and all the variables
5x+11
Back to the equation:
-(5x+11)
-5x-11+41=0
We add all the numbers together, and all the variables
-5x+30=0
We move all terms containing x to the left, all other terms to the right
-5x=-30
x=-30/-5
x=+6
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