-6-2(1+3k)=(3k-1)

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Solution for -6-2(1+3k)=(3k-1) equation: 



-6-2(1+3k)=(3k-1)

We move all terms to the left:

-6-2(1+3k)-((3k-1))=0

We add all the numbers together, and all the variables

-2(3k+1)-((3k-1))-6=0

We multiply parentheses

-6k-((3k-1))-2-6=0



We calculate terms in parentheses: -((3k-1)), so:

(3k-1)

We get rid of parentheses

3k-1

Back to the equation:

-(3k-1)



We add all the numbers together, and all the variables

-6k-(3k-1)-8=0

We get rid of parentheses

-6k-3k+1-8=0

We add all the numbers together, and all the variables

-9k-7=0

We move all terms containing k to the left, all other terms to the right

-9k=7

k=7/-9

k=-7/9

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