41+3y-11=13y-12-4y

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Solution for 41+3y-11=13y-12-4y equation: 



41+3y-11=13y-12-4y

We move all terms to the left:

41+3y-11-(13y-12-4y)=0

We add all the numbers together, and all the variables

3y-(9y-12)+41-11=0

We add all the numbers together, and all the variables

3y-(9y-12)+30=0

We get rid of parentheses

3y-9y+12+30=0

We add all the numbers together, and all the variables

-6y+42=0

We move all terms containing y to the left, all other terms to the right

-6y=-42

y=-42/-6

y=+7

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