-3k-2=2(k+2)

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Solution for -3k-2=2(k+2) equation: 



-3k-2=2(k+2)

We move all terms to the left:

-3k-2-(2(k+2))=0



We calculate terms in parentheses: -(2(k+2)), so:

2(k+2)

We multiply parentheses

2k+4

Back to the equation:

-(2k+4)



We get rid of parentheses

-3k-2k-4-2=0

We add all the numbers together, and all the variables

-5k-6=0

We move all terms containing k to the left, all other terms to the right

-5k=6

k=6/-5

k=-1+1/5

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