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7+(2)/(5)y=(3)/(5)y-4
We move all terms to the left:
7+(2)/(5)y-((3)/(5)y-4)=0
Domain of the equation: 5y!=0
y!=0/5
y!=0
y∈R
Domain of the equation: 5y-4)!=0We get rid of parentheses
y∈R
2/5y-3/5y+4+7=0
We multiply all the terms by the denominator
4*5y+7*5y+2-3=0
We add all the numbers together, and all the variables
4*5y+7*5y-1=0
Wy multiply elements
20y+35y-1=0
We add all the numbers together, and all the variables
55y-1=0
We move all terms containing y to the left, all other terms to the right
55y=1
y=1/55
y=1/55
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