40x+x2=329

Solution for 40x+x2=329 equation:

40x+x2=329

We move all terms to the left:

40x+x2-(329)=0

We add all the numbers together, and all the variables

x^2+40x-329=0

a = 1; b = 40; c = -329;
Δ = b2-4ac
Δ = 402-4·1·(-329)
Δ = 2916
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2916}=54$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-54}{2*1}=\frac{-94}{2}
=-47
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+54}{2*1}=\frac{14}{2}
=7
$