40=8(-b-5)+4(4b+6)

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Solution for 40=8(-b-5)+4(4b+6) equation: 



40=8(-b-5)+4(4b+6)

We move all terms to the left:

40-(8(-b-5)+4(4b+6))=0

We add all the numbers together, and all the variables

-(8(-1b-5)+4(4b+6))+40=0



We calculate terms in parentheses: -(8(-1b-5)+4(4b+6)), so:

8(-1b-5)+4(4b+6)

We multiply parentheses

-8b+16b-40+24

We add all the numbers together, and all the variables

8b-16

Back to the equation:

-(8b-16)



We get rid of parentheses

-8b+16+40=0

We add all the numbers together, and all the variables

-8b+56=0

We move all terms containing b to the left, all other terms to the right

-8b=-56

b=-56/-8

b=+7

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