5(7+b)-(b-4)=71

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Solution for 5(7+b)-(b-4)=71 equation: 



5(7+b)-(b-4)=71

We move all terms to the left:

5(7+b)-(b-4)-(71)=0

We add all the numbers together, and all the variables

5(b+7)-(b-4)-71=0

We multiply parentheses

5b-(b-4)+35-71=0

We get rid of parentheses

5b-b+4+35-71=0

We add all the numbers together, and all the variables

4b-32=0

We move all terms containing b to the left, all other terms to the right

4b=32

b=32/4

b=8

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