40=5/9f-32

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Solution for 40=5/9f-32 equation: 



40=5/9f-32

We move all terms to the left:

40-(5/9f-32)=0



Domain of the equation: 9f-32)!=0

f∈R



We get rid of parentheses

-5/9f+32+40=0

We multiply all the terms by the denominator


32*9f+40*9f-5=0

Wy multiply elements

288f+360f-5=0

We add all the numbers together, and all the variables

648f-5=0

We move all terms containing f to the left, all other terms to the right

648f=5

f=5/648

f=5/648

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