2(2x-6)+2(3x+2)=72

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Solution for 2(2x-6)+2(3x+2)=72 equation: 



2(2x-6)+2(3x+2)=72

We move all terms to the left:

2(2x-6)+2(3x+2)-(72)=0

We multiply parentheses

4x+6x-12+4-72=0

We add all the numbers together, and all the variables

10x-80=0

We move all terms containing x to the left, all other terms to the right

10x=80

x=80/10

x=8

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