40=4y+(2y-4)

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Solution for 40=4y+(2y-4) equation: 



40=4y+(2y-4)

We move all terms to the left:

40-(4y+(2y-4))=0



We calculate terms in parentheses: -(4y+(2y-4)), so:

4y+(2y-4)

We get rid of parentheses

4y+2y-4

We add all the numbers together, and all the variables

6y-4

Back to the equation:

-(6y-4)



We get rid of parentheses

-6y+4+40=0

We add all the numbers together, and all the variables

-6y+44=0

We move all terms containing y to the left, all other terms to the right

-6y=-44

y=-44/-6

y=7+1/3

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