3x=10-(2+x)

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Solution for 3x=10-(2+x) equation: 



3x=10-(2+x)

We move all terms to the left:

3x-(10-(2+x))=0

We add all the numbers together, and all the variables

3x-(10-(x+2))=0



We calculate terms in parentheses: -(10-(x+2)), so:

10-(x+2)

determiningTheFunctionDomain
-(x+2)+10

We get rid of parentheses

-x-2+10

We add all the numbers together, and all the variables

-1x+8

Back to the equation:

-(-1x+8)



We get rid of parentheses

3x+1x-8=0

We add all the numbers together, and all the variables

4x-8=0

We move all terms containing x to the left, all other terms to the right

4x=8

x=8/4

x=2

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