26+4(12u-5)=128

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Solution for 26+4(12u-5)=128 equation: 



26+4(12u-5)=128

We move all terms to the left:

26+4(12u-5)-(128)=0

We add all the numbers together, and all the variables

4(12u-5)-102=0

We multiply parentheses

48u-20-102=0

We add all the numbers together, and all the variables

48u-122=0

We move all terms containing u to the left, all other terms to the right

48u=122

u=122/48

u=2+13/24

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