40=-7-5(5+3b)

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Solution for 40=-7-5(5+3b) equation:



40=-7-5(5+3b)
We move all terms to the left:
40-(-7-5(5+3b))=0
We add all the numbers together, and all the variables
-(-7-5(3b+5))+40=0
We calculate terms in parentheses: -(-7-5(3b+5)), so:
-7-5(3b+5)
determiningTheFunctionDomain -5(3b+5)-7
We multiply parentheses
-15b-25-7
We add all the numbers together, and all the variables
-15b-32
Back to the equation:
-(-15b-32)
We get rid of parentheses
15b+32+40=0
We add all the numbers together, and all the variables
15b+72=0
We move all terms containing b to the left, all other terms to the right
15b=-72
b=-72/15
b=-4+4/5

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