(8x-7)(6x-4)=0

Solution for (8x-7)(6x-4)=0 equation:

(8x-7)(6x-4)=0

We multiply parentheses ..

(+48x^2-32x-42x+28)=0

We get rid of parentheses

48x^2-32x-42x+28=0

We add all the numbers together, and all the variables

48x^2-74x+28=0

a = 48; b = -74; c = +28;
Δ = b2-4ac
Δ = -742-4·48·28
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-74)-10}{2*48}=\frac{64}{96}
=2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-74)+10}{2*48}=\frac{84}{96}
=7/8
$