40=-7(c-8)+3c

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Solution for 40=-7(c-8)+3c equation: 



40=-7(c-8)+3c

We move all terms to the left:

40-(-7(c-8)+3c)=0



We calculate terms in parentheses: -(-7(c-8)+3c), so:

-7(c-8)+3c

We add all the numbers together, and all the variables

3c-7(c-8)

We multiply parentheses

3c-7c+56

We add all the numbers together, and all the variables

-4c+56

Back to the equation:

-(-4c+56)



We get rid of parentheses

4c-56+40=0

We add all the numbers together, and all the variables

4c-16=0

We move all terms containing c to the left, all other terms to the right

4c=16

c=16/4

c=4

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