(x-7)(9x+1)+50=(3x-5)(3x+2)

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Solution for (x-7)(9x+1)+50=(3x-5)(3x+2) equation: 



(x-7)(9x+1)+50=(3x-5)(3x+2)

We move all terms to the left:

(x-7)(9x+1)+50-((3x-5)(3x+2))=0

We multiply parentheses ..

(+9x^2+x-63x-7)-((3x-5)(3x+2))+50=0



We calculate terms in parentheses: -((3x-5)(3x+2)), so:

(3x-5)(3x+2)

We multiply parentheses ..

(+9x^2+6x-15x-10)

We get rid of parentheses

9x^2+6x-15x-10

We add all the numbers together, and all the variables

9x^2-9x-10

Back to the equation:

-(9x^2-9x-10)



We get rid of parentheses

9x^2-9x^2+x-63x+9x-7+10+50=0

We add all the numbers together, and all the variables

-53x+53=0

We move all terms containing x to the left, all other terms to the right

-53x=-53

x=-53/-53

x=1

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