3x(4x-5)-10x+5=5x(x-4)+4

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Solution for 3x(4x-5)-10x+5=5x(x-4)+4 equation: 



3x(4x-5)-10x+5=5x(x-4)+4

We move all terms to the left:

3x(4x-5)-10x+5-(5x(x-4)+4)=0

We add all the numbers together, and all the variables

-10x+3x(4x-5)-(5x(x-4)+4)+5=0

We multiply parentheses

12x^2-10x-15x-(5x(x-4)+4)+5=0



We calculate terms in parentheses: -(5x(x-4)+4), so:

5x(x-4)+4

We multiply parentheses

5x^2-20x+4

Back to the equation:

-(5x^2-20x+4)



We add all the numbers together, and all the variables

12x^2-25x-(5x^2-20x+4)+5=0

We get rid of parentheses

12x^2-5x^2-25x+20x-4+5=0

We add all the numbers together, and all the variables

7x^2-5x+1=0

a = 7; b = -5; c = +1;
Δ = b2-4ac
Δ = -52-4·7·1
Δ = -3
Delta is less than zero, so there is no solution for the equation

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