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40=-1/3(2x+30)+2
We move all terms to the left:
40-(-1/3(2x+30)+2)=0
Domain of the equation: 3(2x+30)+2)!=0We multiply all the terms by the denominator
x∈R
-(-1+40*3(2x+30)+2)=0
We calculate terms in parentheses: -(-1+40*3(2x+30)+2), so:We add all the numbers together, and all the variables
-1+40*3(2x+30)+2
determiningTheFunctionDomain 40*3(2x+30)-1+2
We add all the numbers together, and all the variables
40*3(2x+30)+1
Wy multiply elements
120x(2+1
Back to the equation:
-(120x(2+1)
-(120x3=0
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