(3x-1)+(67-x)+(5x-40)=180

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Solution for (3x-1)+(67-x)+(5x-40)=180 equation: 



(3x-1)+(67-x)+(5x-40)=180

We move all terms to the left:

(3x-1)+(67-x)+(5x-40)-(180)=0

We add all the numbers together, and all the variables

(3x-1)+(-1x+67)+(5x-40)-180=0

We get rid of parentheses

3x-1x+5x-1+67-40-180=0

We add all the numbers together, and all the variables

7x-154=0

We move all terms containing x to the left, all other terms to the right

7x=154

x=154/7

x=22

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