40=(3x-5)=-4(2x-1)

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Solution for 40=(3x-5)=-4(2x-1) equation: 



40=(3x-5)=-4(2x-1)

We move all terms to the left:

40-((3x-5))=0



We calculate terms in parentheses: -((3x-5)), so:

(3x-5)

We get rid of parentheses

3x-5

Back to the equation:

-(3x-5)



We get rid of parentheses

-3x+5+40=0

We add all the numbers together, and all the variables

-3x+45=0

We move all terms containing x to the left, all other terms to the right

-3x=-45

x=-45/-3

x=+15

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